please can anyone help me with this homework i do not know what to do. thank you
1.
Write a program that will count from any user-inputted number to 0. For example, if the user inputs 5, the program should output: 5, 4, 3, 2, 1, 0.
825 0 Newbie Poster
thines01 401 Postaholic Team Colleague Featured Poster
Do you actually need the comma character also?
If not, check this out:
It is fixed to take only a single digit number.
; CntDown
mov SI, 005Dh ; location of command-line parameter
mov cx, [SI] ; put value in CX
cmp cl, 20h ; Is the value empty?
je quit ; if so, quit
print_it: ;
mov ch, 24h ; Put a dollar-sign (terminator) (reversed)
mov [si], cx ; Move that value and dollar sign to command-line
mov ah, 09h ; Prepare to print
mov dx, 005dh ; ...from command-line memory
int 21h ; Print it.
dec cl ; decrement value
cmp cl, 2Fh ; Is it still above zero (hex 30)?
jne print_it ; if not, print it.
quit:
int 20h ; drop to DOS (the easy way)I couldn't find my book, so I did this from memory.
Goalatio 0 Junior Poster in Training
To take a multi-digit number, you have to write your own string input routine, it does not take a great deal of time.
To create a 'buffer' to store each character
STORAGE times 50 db 0
Allows for up to 50 inputted characters.
To access each position in the buffer, you'd do something similar to
mov [STORAGE + 0],al
Position 0 = Position 1 on the buffer
What I normally do, it use a counter to auto-position each character as they are typed.
mov byte [bx],0
START:
cmp bx,51 ;Check if buffer is full..
je FULLBUFFER ;If it is, flag an error
mov ah,0
int 16h
mov [STORAGE + bx],al
inc bx
jmp START
FULLBUFFER:
put error codes here..I will not write the entire thing for you, the only real hard part is writing your own backspace routines.
NotNull 23 Posting Whiz in Training
You could turn the multi-digit value into unpacked BCDS...
jmp start
buf times 2 db 0
start:
mov dx, buf
mov cx, 2
mov bx, 0
mov ah, 3fh ; Read Dev/File Handle
int 21h
sub byte [buf], 0x30
sub byte [buf+1], 0x30'21'=3231-3030=0201
gilianz 0 Newbie Poster
def main():
x = input("number: ")
while ( x >= 0 ):
print x
x = x - 1
main()
Goalatio 0 Junior Poster in Training
You could, there are a few ways that you can do it. The way I showed is just the way I use and prefer.
b1083 0 Newbie Poster
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