Use modulus operator to convert time

[JHus00]

I need to convert hours into weeks, days, and hours.

My professor was hinting that there might be a way to
do this using the modulus operator but I can't seem to think of a way
that its possible. Can anyone help?

thanks!

[r.stiltskin]

Well, if you use integer division to convert hours into days you would use mod to determine the remainder hours.

[JHus00]

thanks, so would it looks something like this

//convert weeks, days, hours
	      days = hours / 24 %

i dont think thats right, I guess im not really sure how to use the mod in this situation.

[r.stiltskin]

No, you must realize that what you wrote is not correct syntax. You can get the days part by

days = hours / 24;

Getting the remainder is a separate operation. Think about it.

[WaltP]

Take for example you want to convert 7520 seconds into hh:mm:ss. Use integer math
To get hours: hr = sec/(60*60); // int math truncates What's left is: sec = sec - (hr*(60*60)); // remove the #hrs Or using mod: sec = sec % (60*60)); // gives remainder if hrs divided out From here you should be able to do minutes, then figure out how to do your project. It's the same.

[JHus00]

Sorry, if im being difficult. I don't understand what is going on here

(hr*(60*60))

Thanks for your help so far, I do understand this more than I did 30 mins ago.
Edit: I understand whats going on as far as 60*60 = 3600 and thats how many seconds are in an hour. I still dont get how to use this for going from hours to days

[WaltP]

I showed you how it works for hh:mm:ss from seconds.
Your task is to do weeks, days, hours from hours.
It's the same procedure with different numbers. How many hours in a day? How many hours in a week?

Simple as that.

[JHus00]

//convert hours, into weeks, days, hrs
	days = hours / 24;
	hours = hours - (days*(12*2)); // remove the #hrs (to pull out whats left)
	hours = hours % ((12*2)); // gives remainder if hrs divided out (using MOD)

got it! thank you so much!

actually, looks like its even simpler than i thought.

days = hours / 24;	
	hours = hours - (days*(24)); // remove the #hrs (to pull out whats left)
	hours = hours % (24); // gives remainder of hrs divided out (using MOD)

[Fabiana_1]

Arrays Introducción

[cereal]

Hi Fabiana_1,

if you have a question then, please, start a new thread by clicking on Contribute.