Member Avatar for menonnik

I have a code like

int a=10;
a=(++a)+(a++)+(a++)+(a--)+(--a);
printf("%d",a);

this gives the output as 51.

while

printf("%d",(++a)+(a++)+(a++)+(a--)+(--a));

gives 56 as ouput.

can you please explain the flow in both the statements.

Edited by kvprajapati because: Added [code] tags. For easy readability, always wrap programming code within posts in [code] (code blocks).
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Member Avatar for Aia

I have a code like

int a=10;
a=(++a)+(a++)+(a++)+(a--)+(--a);
printf("%d",a);

this gives the output as 51.

while

printf("%d",(++a)+(a++)+(a++)+(a--)+(--a));

gives 56 as ouput.

can you please explain the flow in both the statements.

It doesn't matter how or whether you cook it or broil it. That is undefined behavior, and the only guarantee you'll have is that anything can happen.
Read

Edited by Aia because: n/a
Member Avatar for menonnik

thanks

Member Avatar for JuhaW

It's bad behavier to use many incrementation or decrementation with same variable in same statement. C standard does not support this.

Result depends on compiler, version and optimations on compiler. Order of incrementations could happpen in any order.

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