I was wondering if it is possible to subtract 30 from 4ah? i thought so i can convert the ascii character 'C' to hexadecimal '43', i will just subtract 30h from 43h, then add 30 so it will become 43 again and i will be able to perfrom arithmetic on it, but then i realized, what about when the hexadecimal has letters on it? hmm. help please!
cmsc 0 Light Poster
tesuji 135 Master Poster
I was wondering if it is possible to subtract 30 from 4ah? i thought so i can convert the ascii character 'C' to hexadecimal '43', i will just subtract 30h from 43h, then add 30 so it will become 43 again and i will be able to perfrom arithmetic on it, but then i realized, what about when the hexadecimal has letters on it? hmm. help please!
Hi cmsc,
I am glad that we have solved your other task. Fortunately, your new homework is much more easier than the one which required int inputs, just about a full dozen of instructions, all dealing with 8 bit registers, currently no MULs :cool:
-- tesu
cmsc 0 Light Poster
what's MULs? i really don't know. happy to see your reply :D i really don't know what to do with this. this is the number two in my homework :)
is my approach correct? I'm having doubts with the 4ah - 30h thing.
tesuji 135 Master Poster
Sorry, drop the s, so MUL stands for the unsigend multiply instruction.
Number-two homework? But this one is easy by contrast with your first one.
True, there are reasonable doubts in going that way, Jay-Z usually says. Its really easier because of one hexadecimal digit stands for four binary digits. So start by splitting 8 bits into two nibbles (4bits long, do not mistaken that american word :ooh:)
-- tesu
cmsc 0 Light Poster
so the 4ah will become 4 and a? but both will be stored in al, so how will i be able to separate that?
tesuji 135 Master Poster
so the 4ah will become 4 and a? but both will be stored in al, so how will i be able to separate that?
Hi
Here is some code for processing the lower nibble (e.g. hex digit A of 4AH)
;....
mov dl, [bx] ; 2. processing bits 3 .. 0
and dl, 0fh ; clear bits 7 .. 4
add dl, 30h ; add '0' to make an ascii for output (!)
cmp dl, 3ah ; compare it with 3ah
jb lo ; hex digit '0' .. '9'
add dl, 7h ; hex digit 'A' .. 'F'
lo: int 21h ; doscall, output <cl> on screen
;...
[bx] points to a char array in data segement, for example
chars db 'abcdefghijklmnopqrstuvwxyz' ; to be output by hex$out
cends db ? ; create a symbol to calculate number of chars
; then in code segment load byte ptr to chars array:
mov bx, byte ptr chars ; start offsetNow you should reason how to process higher nibble (e.g. hex digit 4 of 4AH), for that you need a shr instruction (don't use cl reg)
-- tesu
cmsc 0 Light Poster
got it! thank you very much :D
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