Shell Script - Array Variable - Out of Loop

[rmsagar]

I am trying to search files starting with the name properties.* inside a directory and assign to an array. When I try to print the array outside the loop, it shows empty. Inside the do loop, it prints fine. How will make this array global or take the values outside the loop. Please share your thoughts.

#!/bin/bash
NAMES=("")
x=0
find /opt/scripts/ -type f -name "properties.*" | while read FILES
do
   x=$(( $x + 1 ))
   NAMES[$x]=${FILES}
done
   echo ${NAMES[@]}

[shibblez]

It's because when bash creates a subshell for the pipe. A new variable is created in this subshell, updated on each iteration and then discarded when the subshell terminates. The simplest answer is probably to use ksh.

[cfajohnson]

IFS=$'\n'
names=( $(find /opt/scripts/ -type f -name "properties.*") )
IFS=$' \t\n'
printf "%s\n" "${names[@]}"