string comparision in windows and linux

[ztdep]

Dear friends:
I get different resutls when copy my code from windows to linux system.
the string comparion " if( keyword==Key[0] ) " is true in window system, but it is false in linux system. I am really confused about this.I copy the same source code and the same input file from window to linux system.I use vs2008 in windows 7, and g++ in open suse linux 11.4.

Could you please give me some information about that.

Key[0]="NODAL COORDINATES";
		   Key[1]="ELEMENT GROUPS";
		   Key[2]="ENTITY NAME:   GEOM                ";

while( !infile.eof() )
				 {     getline(infile,keyword,'\n');  // '\n' is a end 
			             if( keyword==Key[0] )   
							 { 
                                                            // read the points coordinates

     }						          }

[danb737]

Just a wild guess. Would there be a problem because Windows end of line are \r\n, while Unix end of line are \n only ?

[Salem]

# while( !infile.eof() )
Don't use eof() to control the loop
http://sourceforge.net/apps/mediawiki/cpwiki/index.php?title=Feof

When you copied the data file, did you copy it in binary mode, or text mode?
That is, did you convert the \r\n line endings of windows into the \n line endings of Linux?

Use the debugger to see if all the strings you're reading have \r at the end (on Linux).

[ztdep]

I copy the text file from windows to linux directly.
Could you please tell me how you convert the \r\n line endings of windows into the \n line endings of Linux
Regards

[Salem]

http://www.virtualhelp.me/linux/164-dos2unix-missing-ubuntu-1004
Depending on your distro, find and download something called 'dos2unix'

[mrnutty]

Are you comparing char* to char*? It depends on the datatype of keyword. If so then consider using strcmp function of change from char* to std::string