#include<>stdio.h
main()
{
int n,s=0,i=1;
L1:printf("enter a range of numbers:");
scanf("%d",&n)
if(n<1){printf("\wrong input");
goto L1;}
while
{
s+=i;
i+=2;
}
printf("\nthe sum of the series is=%d,s");
getch();
}the above program is meant to find out the sum S=1+3+5+7+....+N
can any on explain me,the significance of talking i+=2??
well in my opinion the way you use your while loop is wrong but if you care to know why i+=2 has to be there. i will say it is there to increment by two each time the while loop runs but there no way on earth your code is going to prints a series no equation for that.
can any on explain me,the significance of talking i+=2??
It's a shorthand version of i = i + 2;
printf("Sum of sequence is %i.", (n+1) * (n+1) / 4))
is the given code correct??
there is no condition for the while loop
it will be displaying an error
In while no condition.:icon_surprised:
printf("\nthe sum of the series is=%d,s");
it should be
printf("\nthe sum of the series is=%d",s);#include<>stdio.h
it should be
#include<stdio.h>Your correction version of code:-
#include<stdio.h>
main()
{
int n,s=0,i=1;
L1:printf("enter a range of numbers:");
scanf("%d",&n);
if(n<1){printf("\nwrong input");
goto L1;}
while(n--)
{
s+=i;
i+=2;
}
printf("\nthe sum of the series is=%d",s);
}now
the above program is meant to find out the sum S=1+3+5+7+....+N
can any on explain me,the significance of talking i+=2??
Here in the sum of n odd positive numbers, numbers are incremented by difference of 2. so every time i is incremented by 2. i+=2 is shorthand of i=i+2;
can any on explain me,the significance of talking i+=2??
it is used for getting the number 3 after 1.If you use i++, it means 1 then 2then 3 etc.
But your program does not do the right.
The actual logic is....
int main()
{
int num,sum=0,m,n;
scanf("d",&n);
m=1;
while(m<=n)
{sum=sum+m;
m+=2;
}
printf("d",sum);The actual logic is....
int main() { int num,sum=0,m,n; scanf("d",&n); m=1; while(m<=n) {sum=sum+m; m+=2; } printf("d",sum);
yes this has to be done
The actual logic is....
yes this has to be done
I am taking summation upto n terms..
I am taking summation upto n terms..
ok
I am taking summation upto n terms..
My code also do the n term. Here n has a value.
My code also do the n term. Here n has a value.
check output for n=3 and n=4
check output for n=3 and n=4
Can you say whats wrong with n=3 and n=4 ?
I do not find any thing wrong.
I have mistecked in my first post of this thread that is
scanf("%d",&n)
Can you say whats wrong with n=3 and n=4 ?
If you are talking summation of n terms your code outputs 4 for n=3 and outputs 4 for n=4.
means 3rd and 4th terms are 4.
where summation of 3 terms is :- 1+3+5=9.
and summation of 4 terms is :- 1+3+5+7=16.
If you are talking summation of n terms your code outputs 4 for n=3 and outputs 4 for n=4.
Misunderstanding!!!!
In my code the "n" is the last digit(range) of the sequence.
Like....
for n=4....1+3=4
and for n=5....1+3+5=9.
If you want like your logic , sum 0f the first n digits where I+=2, it will possible also, I need to coding again.
No dear ,it was not my logic I was correcting his logic and making him understand about the increment.
my code is:
#include<stdio.h>
int main()
{
int n;
scanf("%d",&n);
printf("sum of 1st odd n terms:-%d",n*n);
return 0;
}it was not my logic I was correcting his logic and making him understand about the increment.
Yea I understood.I have said the same thing in my last post>
Misunderstanding!!!!
Yep that was there which I want to tell you I am talking about terms.
If you want like your logic , sum 0f the first n digits where I+=2, it will possible also, I need to coding again.
I dont understand what are you trying to prove or show...???
I am here just for learning and helping others if i can not for an argument and frankly speaking I dont like the way u talked.
I request administrator to please stop such things and proudy talks here, may hurt any one.
Hey cse.avinash
I just say I do not understand what you want to say with my code such as check output for n=3 and n=4 .Your concept was not clear to me.But
If you are talking summation of n terms your code outputs 4 for n=3 and outputs 4 for n=4.
means 3rd and 4th terms are 4.
where summation of 3 terms is :- 1+3+5=9.
and summation of 4 terms is :- 1+3+5+7=16.
It has kept clear all to me.
This is our misunderstanding nothing else.
OK.
Onlineshade
Hmm okay... :)
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