Roman Numbers C

[terence193]

I am currently trying to write a program to simply output roman numerals (not convert-as on many previous threads) from 1-99..
This is the logic/code I have tried so far, but I am certain that it isn't correct apart from the fact that it isnt compiling.

#include<stdio.h>
int main(void)
{
	int x[3],xfront,xback,i;
	xfront=x/10;
	xback=x%10;

	switch (xback=x[2])  {
		case '1' : printf("I");
		break;
		case '2' : printf("II");
		break;
		case '3' : printf("III");
		break;
		case '4' : printf("IV");
		break;
		case '5' : printf("V");
		break;
		case '6' : printf("VI");
		break;
		case '7' : printf("VII");
		break;
		case '8' : printf("VIII");
		break;
		case '9' : printf("IX");
		break;
		default : printf(" ");
		}

	switch (xfront=x[1]) {
		case '1' : printf("X");
		break;
		case '2' : printf("XX");
		break;
		case '3' : printf("XXX");
		break;
		case '4' : printf("XL");
		break;
		case '5' : printf("L");
		break;
		case '6' : printf("LX");
		break;
		case '7' : printf("LXX");
		break;
		case '8' : printf("LXXX");
		break;
		case '9' : printf("XC");
		break;
		default : printf(" ");
 		}
		
		for (x=1;x<=99;x++) 
		{
		printf("%d%d",xfront,xback);
		}
		
	getchar ();
	getchar ();
	return 0;
}

For example when i declared variable x[3] i was referring to 3 spaces to store memory in _ _ \0, so that the first space will be the xfront and the second xback.

But when i wrote the loop i had to do the counter i.e. x from 1-99 and the compiler gave an error.

i tried to remediate to this by :

y=*x;
		for (y=1;y<=99;y++) 
		{
		printf("%d%d",xfront,xback);

[WaltP]

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[terence193]

well let me adapt the question in a manner that perhaps makes more sense then.

The purpose of the program is to output the roman numerals from 1-99 (and use the switch statement)

From the code above how can is there a simple way where I can initialize the variables xback and xfront please such that they refer to the second and first value of x respectively?

[TrustyTony]

Maybe you should put something more in this loop:

for (x=1;x<=99;x++) 
		{
		printf("%d%d",xfront,xback);
		}

Nothing gives roman numbers here, xfront and xback do not change, only counter changes and it is not used for anything.

I would make one function called roman_number taking int argument. I would then print roman_number(x).

[thines01]

When do you put a value in x?
...and is x supposed to be an array of three integers?

[terence193]

I changed the first part to the following

{
int i, front, back;
for(i=1; i<=100; i++)
{
front = i/10;
back = i%10;

and included the two switch statements in this for loop .. where x[1] and x[2] where replaced by front and back and the program worked fine then.