how to update database column

[Amiet Mhaske]

Hi, guys. I am working on vb project, which will save client database.

I've done the coding of ADD, NEW, SAVE, EDIT button. Now, I am stuck at DELETE button. When I delete any particular client then I want my client_id (it's a column in my access database) should get updated (like if I have five clients in database and if I delete 3rd client, then the client_id should start from 1,2,3,4; not like 1,2,4,5)

I am using ADODB and Ms-access at backend, please help!!!!!

[WaltP]

With what? We have no idea what you've done!

[boilerplate_help_info]

Posting requests for help must be well thought out if you want help quickly and correctly.  Your post did not meet the criteria for quality help. You may get some posts, but are they going to be useful?  Check your post with these checkpoints - what is it [i]you[/i] missed:
[list=1]
[*]Ask a question that can be answered. Do not ask
- What's wrong with my code?
- Why doesn't this work?
- Anything else that does not give us useful information
[*]Post your code.  If we don't know what you did, how can we possibly help?
- Use [b]PROPER FORMATTING[/b] -- see this
- Use CODE Tags so your formatting is preserved.
If we can't follow your code, it's difficult to help. We don't care that you're still working on it. If you want us to read it, it must be readable
[*]Explain what the code is supposed to do.  If we don't know where the target is, how can we help you hit it?
[*]Explain what actually happened! If we don't know where the arrow went when you shot it, how can we tell what went wrong and how far from the target you are?
[*]If you have errors, post them! We can't see your screen.  We can't read your mind. You need to tell us what happened.
[*]Do [b]not[/b] ask for code. We are not a coding service. We will help you fix your code. 
    If anyone posts working code for you, they are a cheater. 
    If you use that code [i]you[/i] are a cheater.
[*]Do [b]not[/b] bore us with how new you are. We can tell by your code.
- Do not apologize. We were all new, and unless you are completely 
  brain dead you will get better.
- Do not ask us to "take it easy on you."
- Do not say "I don't know what's going on." That's obvious since
  you posted for help. Use that time wisely by [b]explaining[/b] as best 
  you can so we can help.
[*][b]Do not post your requirements and nothing else. [/b]We view that as a lazy do-nothing student that wants us to do their work for them. That's cheating and we [i]will[/i] be hard on you.
[*]Do not attach files except when absolutely necessary. Most of us are not going to download file.  Add the information to your post.
[*][b]Do not tell us how urgent it is.[/b] Seriously, for us there is no urgency at all. Many that can help will ignore any URGENT or ASAP requests.
[/list]
Think more about your next post so we don't have to play 20 questions to get the info we need to help you.

[/boilerplate_help_info]

[Amiet Mhaske]

for DELETE command I've done following coding:

Private Sub cmdDelete_Click()

If rs.State = 1 Then rs.Close
admincon.Execute "delete from clientdetails where client_id=" & (lblId.Caption) & ""
MsgBox ("Record is Deleted successfully")
Clear
generateid ' It's a function i am using for generating ids. It's coding is given follow
Unload Me
frmAddClient.Show

End Sub

Coding for generateid:

Public Sub generateid()
Dim i As Integer
i = 1
lblId.Caption = i
If rs.State = 1 Then rs.Close
rs.Open "clientdetails", admincon, adOpenDynamic, adLockOptimistic, adCmdTable
Do
admincon.Execute "update clientdetails set client_id=" & (lblId.Caption) & " where client_id=" & (lblId.Caption) & ""

i = i + 1

Loop While rs.EOF = True

End Sub