Hey guys I have been trying to expand the following code but have had no luck, is there anyway I could also make this code say if the previous character is space or a is comma? Thanks.
//temp is the array ch is a char pointer
if( ch == temp || isspace (*(ch-1)))
char ch = temp[ i - 1]; // i is the current position ; i must be greater than 0
if( ch == ' ' || ch == '\'')or
// i is the current position ; i must be greater than 0
if( temp[ i - 1]== ' ' || temp[ i - 1]== '\'')hi thanks for the reply I couldn't get it to work here is the code at the moment it deals with if it is at the start or previous character is whitespace but i also need the or comma clause.
while((ch = strstr( ch, "test ")) != 0)
{
if( ch == temp || isspace (*(ch-1)))
{
count++;
ch++;
}
else
{
break;
}
}#include <iostream>
int main()
{
char* test = "testing is a'test string";
char* ch = test;
int count = 0;
while( (ch = strstr( ch, "test")) != 0)
{
if ( ch != test )// Check if you are at the beginning of the string
{
ch--;
if( ch[ 0 ] == ' ' || ch[ 0 ] == '\'')
{
count++;
ch ++;
// Output the result
std::cout << count << std::endl;
std::cout << ch << std::endl;
ch ++;
}
}
else
{
count++;
std::cout << count << std::endl;
std::cout << ch << std::endl;
ch++;
}
}
return 0;
}Modify for your requirements.
>>it is at the start or previous character is whitespace but i also need the or comma clause.
just add more || operators on that line!
if( ch == temp || isspace (*(ch-1)) || *(ch-1) == ',')or you could use a switch statement
switch(*(ch-1))
{
case ' ':
case '\t':
case ',':
// blabla
break;
}Thanks for you help guys, in my program at the moment I am trying to count int & char paramters, I have the code that starts the array after the open brace and I am using the code below to give the the parameter count but for some reason the count is wrong, it says I have 8 ints and 4 chars any idea where i went wrong? Thanks.
//text file contents
int test (int f, int k, char u,int f, int a, char h)while((ch = strstr( ch, "int ")) != 0)
{
if( ch == temp || isspace (*(ch-1)) || *(ch-1) == ',')
{
intCount++;
ch++;
}
else
{
break;
}
}
ch=temp;
while((ch = strstr( ch, "char ")) != 0)
{
if( ch == temp || isspace (*(ch-1)) || *(ch-1) == ',')
{
charCount++;
ch++;
}
else
{
break;
}
}see if this helps.
#include <string.h>
#include <stdlib.h>
#include <stdio.h>
#include <ctype.h>
int getCount(char* string,char* dataType)
{
int counter = 0;
char* ch = string;
while((ch = strstr( ch, dataType)) != 0)
{
if( ch && ch == string || isspace (*(ch-1)) || *(ch-1) == ','|| *(ch-1) == '(')
{
counter++;
// bypass everything up to the next space
while(!isspace(*ch))
ch++;
}
else
{
break;
}
}
return counter;
}
int main(int argc, char* argv[])
{
char str[] = "int foo(int f, int k, char u,int f, int a, char h)";
int intCount;
int charCount;
intCount = getCount(str,"int ");
charCount = getCount(str,"char ");
printf("intCount: %d charCount: %d\n",intCount,charCount);
return 0;
}Can you give me any advice acient dragon?
Can you give me any advice acient dragon?
Yes, learn to read and comprehend what you read. I posted working code for you. Compare it with what you have to see what you are doing wrong.
thanks I will look into it now
I am still getting the wrong number of ints (8) and chars(4) the only difference between the code I tested and the code you have is that I started the array after the first brace and the array data was obtained from a text file so it was:
int f, int k, char u,int f, int a, char h)
I am also not sure what the following does?
ch && ch == stringCould the problem be with the way I am using arrays or does it matter that some parameters may have whitespace after the comma and some don't?
Thanks again.
>>the only difference between the code I tested and the code you have is that I started the array after the first brace and the array data was obtained from a text file so it was:
No it isn't. Check the loop very carefully -- the if statement is larger and there is a while statement you do not have.
repost your current program.
>>or does it matter that some parameters may have whitespace after the comma and some don't?
That should not be a problem because the if statement is checking for both conditions.
Hi this is my code I have the longer if and extra while loop.
I am still using the same test data and it says there is 8 ints when there should only be 4 as I started the array just after the first brace.
void test(char* temp)
{
char * ch=temp;
while((ch = strstr( ch, "int ")) != 0)
{
if( ch && ch == temp || isspace (*(ch-1)) || *(ch-1) == ','|| *(ch-1) == '(')
{
iCount++;
while(!isspace(*ch))
ch++;
}
else
{
break;
}
}
cout<<"no of ints: "<<icount<<endl;
}Thanks I have got it sorted but I was just wondering what the following part of the code does:
if(ch && ch == stringthanks again
char[]//set the number of required in the memory eg
char bradley[10]
Thanks I have got it sorted but I was just wondering what the following part of the code does:
if(ch && ch == stringthanks again
remove the "ch &&" -- its reduncent and not needed. That just checks to see that ch != NULL, but it can't be NULL when it reaches the if satement due to the line above it.
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