I am writing a program about giving change. But I am having issues with getting remainders for decimal numbers.
For instance I am giving $46.63 change
I want to know how many $20.00 bills it has, I would have to divide it by 20.
46.63 / 20 = 2.3315
My question is how can I get the .3315?
The problem is that % does not work with double, I tried it with integer, but I just can't get the cents.
so convert everything to cents
multiply up by 100 convert to int, use %, then convert results back to double
@AD??
so convert everything to cents
multiply up by 100 convert to int, use %, then convert results back to double
Multiply the $46.63 by 100 that's what you mean.
Would it be like this 46.63 * 100 % 20?
46.63 / 20 = 2.3315
No. double x=23.56
x*=100
iny y=(int)x
then use %
No. double x=23.56
x*=100
iny y=(int)x
then use %
I am trying to figure how the code works, but I still don't get it since I am beginner in programming.
Did you mean?
double x = 46.63; That's the value that was given.
x = 100;
int y = (int)x; then use %.
I've been trying numerous time to covert int to double, I always get an error in the code.
ok x=46.63
x = 100 * x // same as x*=100 ie x now equals 4663
google casting in c++
then work on ints using modulus
edit: the number i used was just random
double x = 46.62;
int cents = (int)x * 100;
int twenties = cents/(20*100);
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