String Handing : Char with array inside if statement

[jember]

Please hep me with this problem: I am having a problem with string handling using c language. This is actually an assignment.

Here's how the whole program must work:
1. User must input a valid password
2. Once the user inputted a valid password, it will access to an employee's database
3. After the user's identity is confirmed, it will display the employee's current status at work (name, position, employee's ID NO. and Net salary) and will ask the user whether to change employee's net salary or not.
4. The computation for net salary continues once the user decided to proceed the process of changing the employee's net salary.
5. After computing, it will display the new data for the employee and will ask again to change the employee's net salary.

I am almost done with this assignment but I'm still not contented for I want the password to be in Char Datatype. Of course, it is obvious that users might not know that the password must be in numbers. So I prefer it to make it string but in C, there is no such thing as a String Datatype. I have to use char datatype to be able to use strings.
I want the program to accept char variables when entering a valid password.

I am using Dev C++ for this program.

Here's the main problem in my program that I wanted to change:

long int password[7]={11201993}; // valid password

AND

if (password[7] !=11201993)

**If you have other suggestions, please let me know, too. Thank you :)**

This is the whole coding of my program:

#include <stdio.h>
#include <stdlib.h>
     void design_one(); //function dispaying design
     void db__intro(); //function displaying intro message
     void sal(double); //function displaying computed net salary and other computations
main()
{

 char execute; // for database execution
 double Net_sal; //for net sal() function
 long int password[7]={11201993}; // valid password
 int d; // for net sal execution
//
              design_one();
//
     printf ("Welcome to Jem's Database! In order to access her files,\n\t  \t\tyou need to enter a valid password!");
     printf("\n\n\tProceed to enter database? (y/n): ");
     scanf ("%c", &execute);
//user decides whether to execute database or not
 switch(execute)
{
 case 'y':
 case 'Y':
//if user decided to enter the database
     printf ("\n\tPassword? : ");
            repeat://input locztion for goto
     scanf ("%i", &password[7]);
//user must input password
  if (password[7] !=11201993)
{
     printf ("\n\tInvalid password! Please type the correct one: ");
            goto repeat;//while password is not correctly entered, it will keep asking for a password
}
//if password is correctly entered, it will proceed to the database
  else
{
              system ("cls");
              db__intro(); // shows database intro
 while (d != 0)//while user does not exit database
{
      printf("\n\tEnter command = ");
      scanf("%i", &d); 
  if (d == 0)
{
      exit(0);// program shut down
}    
  if (d==1)
{
         sal(Net_sal);//displays the new database
}
  else//If command is incorrectly entered, it will automatically shut the program 
{
         system ("cls");
    printf("\n\n\n\tPROGRAM MALFUNCTIONED due to program error! Program shutting down.\n\t\t");
         system ("pause");
         exit(0);
}
}

}
                  break;

//if user decides to not continue to the database
  case 'n':
  case 'N':
                  exit(0);// pause the program for a while then proceed to exit.
                  break;
//automatic exit

  default: // if user incorrectly inputted a wrong command, the program will automatically shut down
                  system ("cls");
           printf ("\n\n\n\tSystem error due to invalid input of command! Program shutting down! \n\t");
                  system ("pause");// pause the program for a while then proceed to exit.
                  exit(0);
                  break;
}
getch();      
}

// Upper design;
void design_one()
{
     
     int i, j;
          printf ("|");     
 for (i=0; i<=77; i++)
{
          printf ("-");
}
          printf ("|\n\n\n\t");
}
     
//displays database intro
void db__intro()
{
    
          printf("\n\n\tUSER IDENTITY CONFIRMED! LOADING USER DATA..\n\t");
                             system ("pause");
                             system ("cls");
                             design_one();
          printf("\n\n\tName: Jemimah Beryl M. Sai\tUser ID NO. 310-0384\n\tNet Salary: 30000 Php\t\tCurrent Position: Software Engr."); 
          printf ("\n\n\tPRESS 1 - Change employee's net salary\n\tPRESS 0 - Exit database \n");
}

//computation for net salary of employee
void sal (double ns)
{
     int w_hrs,w_days, otime;
     double w_pay, hr_rate,  taxr, taxc;
          printf("\tAmount of hourly rate: ");
          scanf ("%lf", &hr_rate);
          printf("\tNumber of working hours: ");
          scanf("%i", &w_hrs);
          printf("\tNumber of working days: ");
          scanf ("%i", &w_days);
          printf("\tNumber of over timed hours: ");
          scanf("%i", &otime);
          printf("\tTax Rate:\t");
          scanf("%lf", &taxr);
                           system ("cls");
          w_pay = (((w_hrs+otime)*hr_rate)*w_days);//weekly pay computation
          taxc = w_pay*(taxr/100);//convert tax rate to decimal
          ns=w_pay-taxc;//net salary computation
                           design_one();

          printf("\n\n\tName: Jemimah Beryl M. Sai\tUser ID NO. 310-0384");
          printf("\n\tNet Salary: %.2lf Php\t\tCurrent Position: Software Engr.", ns);
          printf ("\n\n\tWeekly Pay: %.2lf Php", w_pay);
          printf("\n\tHourly Rate: %.2lf Php/hour", hr_rate);
          printf("\n\tWorking Hour(s): %i hours", w_hrs);
          printf("\n\tOvertime Hour(s): %i hours", otime);
          printf("\n\tWorking Days: %i days", w_days);
          printf("\n\tTax rate: %.1lf percent\n", taxr);
                          return ;
}

[WaltP]

Just make the password a character array.

[jember]

Just make the password a character array.

There is an error:
[Warning] comparison between pointer and integer

[zeroliken]

Once you use a character array you need to make specific changes in the program

for example:

scanf ("%i", &password[7])

will be changed to %s for the string input

By changing it to a char array you should be able to make the neccesary changes in the code to make it compatible but if you still need further help with this you could always post all the error messages and their corresponding lines where they're found

P.S. there's no need to downvote WaitP's post, he posted the first step for the solution :)

[Ab000dy_85]

use a function called strcmp(char arr1, "passKeyAnythingHereToMatch")

scanf ("%s", &password)
int strcmp ( const char * str1, const char * str2 ); is the prototype
//Use this instead
 if (strcmp ( password, "11201993" ) != 0) //this mean they are not equal
//if the returned value is 0 then they are equal

[jember]

use a function called strcmp(char arr1, "passKeyAnythingHereToMatch")

scanf ("%s", &password)
int strcmp ( const char * str1, const char * str2 ); is the prototype
//Use this instead
 if (strcmp ( password, "11201993" ) != 0) //this mean they are not equal
//if the returned value is 0 then they are equal

Thank you so much for the idea.. I'm done with my assignment!