#include <stdio.h>
#include <stdlib.h>
main()
{
char a[30];
int i,j,n,temp;
printf("enter the limit: ");
scanf("%d",n);
printf("enter the string: ");
for(i=0;i<n;i++)
{
scanf("%s",a[i]);
}
for(i=0;i<n-1;i++)
{
for(j=i+1;j<n;j++)
{
if(strlen(a[i])>strlen(a[j]))
{
temp=a[j];
a[i]=a[j];
a[j]=a[i];
}
}
}
for(i=0;i<n;i++)
{
printf("%d",a[i]);
}
}
compiler stops working here when executing the program but 0 errors
no iam asking about sorting now
variable a is an single dimensional array which will hold only one string. What you want is something like this: char a[20][30]; which is a 2d array that holds up to 20 strings, and each string can contain up to 30 characters (29 + null terminator).
no iam asking about sorting now
Maybe you should finish learning something before running off to learn something new, because you keep making the same mistakes.
no actually i soretd the words alphabhetically using the same method that worked perfectly see this
#include <stdio.h>
#include <stdlib.h>
void main()
{
char name[10][10],temp[10];
int i,j,n;
printf("enter the limit : ");
scanf("%d",&n);
printf("enter the names: ");
for(i=0;i<n;i++)
scanf("%s",&name[i]);
for(i=0;i<n-1;i++)
for(j=i+1;j<n;j++)
if(strcmp(name[i],name[j])>0)
{
strcpy(temp,name[i]);
strcpy(name[i],name[j]);
strcpy(name[j],temp);
}
printf("the sorted list is \n");
for(i=0;i<n;i++)
{
printf("%s\n",name[i]);
}
}
We're a friendly, industry-focused community of developers, IT pros, digital marketers, and technology enthusiasts meeting, networking, learning, and sharing knowledge.