Hello
I'm quite new to Python and would require some advice. I'm trying to create a picture viewer that changes pictures with regular intervals.
The problem arises when I try to use time.sleep() along my go(), which changes the image.
The code first loads images from a folder and uses go() to change the image. go() is executed by keyEvent().
The code:
def loadImages():
global pixbufs
for file in os.listdir(dir):
filePath=os.path.join(dir, file)
pix=gtk.gdk.pixbuf_new_from_file(filePath)
pix=scaleToBg(pix, bg)
pixbufs.append(pix)
print("Loaded image "+filePath)
def go(relativePos):
global pos
pos+=relativePos
last=len(pixbufs)-1
if pos<0:
pos=last
elif pos>last:
pos=0
image.set_from_pixbuf(pixbufs[pos])
def keyEvent(widget, event):
global pos, image
key = gtk.gdk.keyval_name(event.keyval)
if key=="space" or key=="Page_Down":
go(1)
time.sleep(5)
go(1)
elif key=="b" or key=="Page_Up":
go(-1)
elif key=="q" or key=="F5":
gtk.main_quit()
else:
print("Key "+key+" was pressed")
So, the problem is in the keyEvent() part, where the execution order after pressing "space" is not the one I want. For instance, if I want to change image, wait 5s and change image again, I write:
go(1)
time.sleep(5)
go(1)
but the result is the same as writing:
time.sleep(5)
go(1)
go(1)
The problem seems to be that the time.sleep() is always executed before go() regardless of the writing order in the code. I tried to run the code unbuffered, but it didn't help. How do I get Python to perform the commands in the order that I want? The final program should use a set of pictures and show each picture for a few seconds in a loop. Using a for loop:
for i in range(4):
time.sleep(5)
go(1)
i=i+1
the same problem is present, the code acts as:
time.sleep(20)
go(4)
How do I get this fixed?
Thank you in advance
-Kerma
