I have to print out the numbers -2.3 to 2.9 in increments of 0.4, and then add the poss and neg number
EX:
-2.3 -1.9 -1.5 -1.1 -0.7 -0.3 0.1 0.5 0.9 1.3 1.7 2.1 2.5 2.9
Sum of negative values: -7.8
Sum of positive values: 12
i have gotten a little father than this but my code is all over the board.
#include <iostream.h>
int main() {
for (float counter=-2.3; counter <= 3.0; counter+=.4)
cout << counter << " ";
return 0;
}
add a float counter and then add the value of counter to it within the loop that begins on line 7 of the code you posted.
>> but my code is all over the board.
Looks ok to me, just add the code I mentioned above and you have the answer.
You are very close. You just need to add a couple of things to your loop.
#include <iostream>
using namespace std;
int main()
{
// The sum of no numbers is zero, so...
float sum_of_positive = 0.0;
float sum_of_negative = 0.0;
for (float counter=-2.3; counter <= 3.0; counter+=.4)
{
cout << counter << " ";
// [B]todo: if counter is less than zero, add it to the sum_of_negative[/B]
// [B]todo: same kind of thing for positive numbers[/B]
}
// [B]todo: print out your sums here[/B]
return EXIT_SUCCESS;
}Hope this helps.
[EDIT]
man, too slow again...
fooey.
[EDIT]
man, too slow again...fooey.
Happes to all of us all the time :D
If youre still lost heres some code you can use:
#include <iostream>
using namespace std;
int main()
{
float sum_of_positive = 0.0;
float sum_of_negative = 0.0;
float counter;
for (counter=-2.3; counter <= 3.0; counter+=.4)
{
cout << counter << " ";
if (counter < 0)
sum_of_negative +=counter;
else
sum_of_positive +=counter;
}
cout << "Sum of negative values: " << sum_of_negative;
cout << "Sum of positive values: " << sum_of_positive;
return 0;
}Nobody learns if you just give them answers. My post was as close to it as I dare go.
The trick to programming hasn't anything to do with syntax or language or loops or anything. It is thinking about the problem.
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