Im having arrayoutofbounds error on my code.
import java.io.*;
class s{
public static void main(String args[]) throws IOException{
BufferedReader in=new BufferedReader(new InputStreamReader(System.in));
String[] a = {"X","C","O","M","P","U","T","E","R","S"};
System.out.println("Enter Price: ");
String b = in.readLine();
for(int i=0;i<b.length();i++){
System.out.print(a[b.charAt(i)]);
}
}
}what am i doing wrong here? The output should be if i input 35, should be MU.
and why should that be so? charAt gives the character value at the index indicated.
'3' does not yield 3 though.
In other words, read the API docs for Integer and its parse methods, and see if there is something there that can help you.
And find out what the difference between a char and an int is, as you can use a char as an int (as you've done here), but its value won't be what you seem to be expecting (find an ASCII character code table).
Thank, I needed to convert it into integer. Anyway, I encountered a new problem, How do I get the value of a special character like a PERIOD?
You just cast it. In Java a char is actually just like an int, it only depends on how you use it.
// Declaration of char c, initialized with the character 'a'.
char c = 'a';
// For int value of the character, cast to int: (int).
int i = (int) c;
// Do some work.
i++;
// Get the character back from the int by casting to char: (char).
c = (char) i;
// Now you see why 'b' comes after 'a' in the ascii table.
System.out.println(c);Black Box
We're a friendly, industry-focused community of developers, IT pros, digital marketers, and technology enthusiasts meeting, networking, learning, and sharing knowledge.