Member Avatar for waaliban

Hello friends,
I want to write a javascript to list of all files in a folder including files in the subfolders. This is for the scorm purpose to list all the files. some examples are listing files but not listing the files inside the subdirectories. I want the file's full path like C:\Documents\javascript\wilson.js like this.

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  • 2 Years Discussion Span
  • Latest Post Latest Post by nudelsalat
Member Avatar for essential

Please feel free to modify this code to match your needs. If you have any question regarding this code you can document.write('Me on my inbox'). lol! Have a good day...

<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> 
<html> 
<head> 
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Some Title</title>
<script type="text/javascript">
function showAvailableDrives()
{
document.write( getDriveList() );
} 

function getDriveList()
{ 
var fso, s, n, e, x;
fso = new ActiveXObject('Scripting.FileSystemObject');
e = new Enumerator( fso.Drives );
s = '';
do
{ x = e.item();
s = s + x.DriveLetter;
s += ':- ';
if ( x.DriveType == 3 ) n = x.ShareName;
else if ( x.IsReady ) 
n = x.VolumeName;
else n = '[Drive not ready]';

s += n + '<br>';
e.moveNext();
} 
while ( !e.atEnd() );
return( s );
} 
</script>
</head>
<body>

<p>

<script type="text/javascript"> 
showAvailableDrives(); 
</script>

</p>

</body>

</html>
Member Avatar for svaughn8891

Hello friends,
I want to write a javascript to list of all files in a folder including files in the subfolders. This is for the scorm purpose to list all the files. some examples are listing files but not listing the files inside the subdirectories. I want the file's full path like C:\Documents\javascript\wilson.js like this.

A more web approach to this would be to use the XMLHTTPRequest object to fetch a directory (instead of a file) from a web server. This will bring back an HTML page which list the files in the directory. You can then parse through the html and find the directories. With apache you can recongnize a directory because there will be a link with the href value equal to the text node in the link.

Obviously if the http server doesn't allow listing a directory, this won't work.

Here is some code that I use. The XML.getFile function below just wraps and XMLHTTPRequest.

var operationsHTML = XML.getFile(env + '/operations/').responseText;
   var linkStart = 0
   var linkEnd = 0
   while (linkStart <= linkEnd) {

      linkStart = operationsHTML.indexOf('<a', linkEnd);
      if (linkStart > -1) {

         linkEnd = operationsHTML.indexOf('</a>', linkStart) + 4;
      
         if (linkEnd > -1) {

            var hvs = operationsHTML.indexOf('href="', linkStart) + 6;
            var hve = operationsHTML.indexOf('"', hvs) - 1;

            var tnvs = operationsHTML.indexOf('>', linkStart) + 1;
            var tnve = operationsHTML.indexOf('<', tnvs) - 1;

            if (operationsHTML.substring(hvs, hve) == operationsHTML.substring(tnvs, tnve)) {

               alert(operationsHTML.substring(tnvs, tnve))
               operations[operationsHTML.substring(tnvs, tnve)] = null;
            }
         }
      }
   }

Steve

Edited by Ezzaral because: Added code tags. Please use them to format any code that you post.
Member Avatar for Taywin

Old old thread... 2 years old!!!

Member Avatar for nudelsalat

Old old thread... 2 years old!!!

But unlike your post, svaughn8891s post was helpful for me. Stumbled over it after searching for a solution with google and I'm glad he did answer after 2 years.

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