Member Avatar for paradox814

I need to load a value from a recently posted page...

for ($i=0; $i<10; $i++)
{
     $_SESSION['someVar'][$i] = $_POST['someVar'][$i]
     $_SESSION['anotherVar'][$i] = $_POST['anotherVar'][$i]
     $_SESSION['yetAnotherVar'][$i] = $_POST['yetAnotherVar'][$i]
}

now the session part works just fine, but the $_POST part just blows up on me! How can I fix this? I want to keep the $_POST there, because I know I can just do $someVar[$i] and that will work but it's not what I want to do. I have seen a foreach loop and thought about that. But, would that keep all the variables tied together with the same index? I really dont want to use a foreach loop if I dont have to, but if thats what I need to use, then so be it.

Thanks!

  • 4 Contributors
  • 4 Replies
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  • 1 Day Discussion Span
  • Latest Post Latest Post by Troy
Member Avatar for Troy 
$_SESSION['someVar'][$i] = $_POST['someVar'][$i]

$_POST[$i] is not valid unless your 'someVar' FORM element is an array of checkboxes or you have multiple text fields with the same name. Normally, it would just be $_POST.

Whether it is an array or not, you can just do this:

$_SESSION['someVar'] = $_POST['someVar'];

It does not matter whether 'someVar' is an array or not--the session var will still receive the value.

Member Avatar for zippee

How about this?

$_SESSION['someVar'][$i] = $_POST['someVar'.$i]

In this case, your form variables are someVar1, someVar2,...

Member Avatar for val542

why not using define function!?

commented: Reply is not even applicable to the topic. +0
Member Avatar for Troy

val542, your reply makes no sense. The define() function does not even apply to this scenario.

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