Posts by pzuurveen

you are making 2 calls to call.php
first has post variables:
xhr.send("amount=" + transferTotal + "&name=" + name);

second does not:
window.open('https://mydomain.com/con.php', '_blank');

$_SESSION gets set by session_start()
before that is empty
So:

<?php
    session_start();
    header("Content-Type: application/json");
    header("Access-Control-Allow-Credentials: true");
    header("Access-Control-Allow-Origin: null");

    if (isset($_SESSION))
    {
        $_SESSION["time"] = time();
        if (isset($_SESSION["time"])) echo json_encode("Session exists:" .$_SESSION["time"]);   
    }
    else
    {
        echo json_encode("Session does not exist!");
    }

Why not use explode

code ?

please show your code

remove the style="display:none;" from

    <ul id="playlist1" style="display:none;">
        <?=$output?>
    </ul>

use google.maps.marker()

the deprecated object google.maps.MarkerImage only defines the image.
(the also an example on the same page what to use now)

use IN

UPDATE sho_term_relationships 
   SET term_taxonomy_id = 2
 WHERE object_id IN (SELECT `id` FROM `1876522_shoping`.`sho_posts` WHERE CONVERT(`post_title` USING utf8) LIKE '%Audio CD%')

if (isset($_POST['chkNumberck'])) $returnArray=$_POST['chkNumberck'];
else $chkNumberck= array();
$count=5;

echo"<form action='test.php' method='post'>";
for ($sub_id=0 ;$sub_id < $count;$sub_id+=1) 
    {
    echo "<input type='checkbox' name='chkNumberck[]'  value=$sub_id "; 
    if (in_array($sub_id,$chkNumberck)) echo"checked='checked'";>
    }
echo "<input type='submit' /></form>";

2e part:

       $output ="";
           while($record = mysqli_fetch_assoc($query_confirm)) {
                $output .= "<tr>";
                $output .= "<td>" . $record["p_date"] . "</td>";
                $output .= "<td>" . $record["p_day"] . "</td>";
                $output .= "<td>" . $record["timein"] . "</td>";
                $output .= "<td>" . $record["timeout"] . "</td>";
                $output .= "<td>" . "06:25:22" . "</td>";
                $output .= "<td>" . $record["p_date"] . "</td>";
                $output .= "</tr>";
                }   
            return $output; 

not sure about the 1st part.
Are $dateval1 eand $dateval2 in the proper format?
how is p_date defined? date? dateTime?

also:

echo "<td><a id='more' href='http://www.niloofar3D.ir' onClick='return popup(this, \"mypopup\")'><button>&raquo;</button></a></td>";

is this what you want:

$sql = "SELECT * FROM misscall WHERE did_no = ". $didno;

or did I not understand your question?

silly question:
Are you actually using a Apache server?

maybe if you tell what isn't working

according to the manual: operators precedence

it has an 'Undefined order of evaluation'
and may 'change between versions of PHP or depending on the surrounding code'

html line 9

<input type="submit" name="y" value="submit my data" />

Your submit-button is called 'y' not submit
either change that line or your php_handler.php line 3:

if (isset($_POST['y'])){

get values after decimal

something is wrong at around line 228

if (isset($_POST['type'])) {
    if ($_POST['type'] == "login")
}

change to

if (isset($_POST['type'])) {
        if ($_POST['type'] == "login") {
        // do something 
        // like displaying your login form
        }
    }

Your database login and password are showing
Change them now!!

$id =$_POST['user_id'];

At line 12 $path and $img are not known yet, you declare them later.
So move the php part (line 14 -41) to the top of your script

it must be $d= $_GET["d"];
not $d= $GET["d"];

make sure your browser points to http://localhost/yourfile.php and NOT file://c:/wamp/htdocs/yourfile.php

<?php
session_start();

must be the at the very top of youre script.
no html before it, not even a white-line;

for actual error message:
if just you run session1.php, $_POST will be empty.
test: var_dump($_POST);
the $_POST is filled bij the form only after you submit it
but action="session2.php" will redect to session2.php
so in session2.php $_POST['text'] will have the value input in the form.
So no need for $_SESSION.

What exactly do you need to do?
you need to be a registrar to create a new domain yourself. (and have an dns-server).
But you can create subdomains like somebody.yoursite.com

It looks to me that your database is not structured
properly. Take a look at database normalization

have you tryed:
if (isset($_POST['submit'])) {

should it be :
$mail->Port = 465; //port secure ssl email

have you checked out the php mail function?

do you get any error messages?

quite te project
but to start:
http://codex.wordpress.org/Function_Reference/add_menu_page

You don't do a query
checkout www.tizag.com,
www.w3schools.com

have you checked out move-uploaded-file?
take a look at the example

problably just a past error line 2:
<?phpforeach($row as $b):?>
must be
<?php foreach($row as $b):?>

but where is the endforeach;

if(!empty($stu_fname) &&
   !empty($stu_lname) && 
   !empty($stu_email) && 
   !empty($stu_telp)  && 
   !empty($stu_skype) )  {

to cover the basics:
make sure $_GET["clientid"] is not empty
add: else echo "no clientid";

don't you mean :
no DATAbase selected?

mysql_connect("localhost","root","") or die (mysql_error());
mysql_select_db("secure") or die (mysql_error());

also I don't see a mysql_query();
also mysql is deprecated use mysqli or pdo

Why do you want to do this.
To protect your server from mysql-injection?
Than it's not save to rely upon javascript.
Data can be sent directly to your server bypassing all your code.
Javascript validation is only used to create a faster error message.
It's the job of the server-site script (php) to make sure the data is save.

edit: nevermind

You never execute the update query

$s="UPDATE finance SET credit ='" . $r. "'  WHERE payee = 'rw'";
$res = mysql_query($s) or die(mysql_error());

e.currentTarget.html() should work
html() retuns the html inside of the <div> not the <div> itself

make sure your browser points to http://localhost/
not c:/wamp/www/yourefile.php

if(isset( $_GET['Product_id'])) $product = $_GET['Product_id'];
else echo " no product id";

I didn't give you the solution because you already know it.
isset() will test test if a var exists without giving an error.
Simular as you do on line 1.
empty() whill test if i has a value that is not FALSE
combining the 2:

if( isset($row['PageId']) && !empty($row['PageId']) )   
    {
    $val=$row['PageId'];
    }
else 
    {
    $val='';
    }

That just turns off any error message below E_PARSE level.
It doesnot solve the error.

if $_GET['Id'] (line 1) is not set, $row['PageId'] (line 27) will no exist

JSONReader() is not part of php

Why do you want to know?
Or do you want to know the connection speed?

You have to pay zenatdesign.com $40 to be able to use that software.
Gess they are happy to answer your questions.

in your function you use loginsell but your form is called loginform