does anyone know how to make a binary to decimal converter????

[al3x748769]

i am new to C and i am trying to learn more as i am taking a basic class. we started out with basic programs and now we are making a tic tac toe board. i was wondering what a 8 bit binary counter would look like. i know the formula but dont know how you would apply it in C

[al3x748769]

the formula that i know is

10110101= 1( 2^7) + 0( 2^6) +1( 2^5) +1( 2^4) +0( 2^3) +1( 2^2) +0( 2^1) +1( 2^0)

[Aia]

Example

[al3x748769]

yeah like the code u would write. like i would like to see it. i have no idea how u would bring each bit to the formula and stuff like that

[al3x748769]

does anyone know???

[sillyboy]

write it yourself, at least show some effort and you will get better help.

[Aia]

does anyone know???

Did you click in the example link I posted?

[al3x748769]

i clicked the example link. i still dont kno how to finish it i am sure it is something very easy. can someone help me if we have this code what would i need to add to get it to be a 8 bit counter... ali is a big help... also could someone explain what they did. please help

#include <stdio.h>

/* Convert the text representation of a binary number into an integral value. */

unsigned int btou(const char *bit)
{
unsigned int value = 0;
while ( *bit != NULL ) /* loop through all of the text representation */
{
value *= 2; /* double the previous result */
value += *bit - '0'; /* add current bit (0 or 1 from '0' or '1')*/ ++bit; /* go on to the next bit */
}
return value;
}
int main ( void )
{ static const char *binary[] =
{ "0000","0001","0010","0011","0100","0101","0110","0111", "1000","1001","1010","1011","1100","1101","1110","1111", "1010010110100101", "11011110101011011011111011101111",
};
size_t i;
for ( i = 0; i < sizeof binary / sizeof *binary; ++i )
{
unsigned int value = btou(binary);
printf("btou(\"%s\") = 0x%X = %u\n", binary, value, value);
}
return 0;
} /*
my outputbtou("0000") = 0x0 = 0
btou("0001") = 0x1 = 1
btou("0010") = 0x2 = 2
btou("0011") = 0x3 = 3
btou("0100") = 0x4 = 4
btou("0101") = 0x5 = 5
btou("0110") = 0x6 = 6
btou("0111") = 0x7 = 7
btou("1000") = 0x8 = 8
btou("1001") = 0x9 = 9
btou("1010") = 0xA = 10
btou("1011") = 0xB = 11
btou("1100") = 0xC = 12
btou("1101") = 0xD = 13
btou("1110") = 0xE = 14
btou("1111") = 0xF = 15
btou("1010010110100101") = 0xA5A5 = 42405
btou("11011110101011011011111011101111") = 0xDEADBEEF = 3735928559*/

#if 0
/* of course, if you can use standard library functions, it would be simpler yet */
#include <stdlib.h>
unsigned int btou(const char *bit)
{
return strtoul(bit, NULL, 2);
}
#endif

[al3x748769]

i kno that ou putan binarry [] that is the only change i can really see.
{ static const char *binary[8] =
{ "0000","0001","0010","0011","0100","0101","0110","0111", "1000","1001","1010","1011","1100","1101","1110","1111", "1010010110100101", "11011110101011011011111011101111",

also what about the i all over the place
size_t i;
for ( i = 0; i < sizeof binary / sizeof *binary; ++i )

[al3x748769]

/* Binary to Decimal **********************************************************/
me and an old friend worked on this freshman year but i cant have the bool and need it in


#include "stdafx.h"
#include <stdio.h>


instead of


#include <iostream>
#include <cstdio>
using namespace std;


bool binary[8]; // unused, but if you need to store it, it will be in here
char str[8];    // input string
int result;     // integer result
int power = 1;  // power of 2. This is needed because of (2 ^ i) problem (see below)


int main(void)
{
do
{
cout << "Please input an 8 bit binary number or type q to quit:";
cin >> str;


result = 0; // reset to 0
power = 1;  // first power = 2 ^ 0 = 1


/* convert it */
for(int i = 0; i < 8; i++)
{
if(str == '1')
{
binary = 1;// make binary number
result += power; // modify result
}
power *= 2; /* id like to use 2 ^ i instead of power but it
DOESNT give 1, 2, 4, 8, 16 ect... */
}


/* output */
cout << "\nThe binary number " << str << " = " << result << "\n";
} while (str[0] != 'q');   // do - while until "q" is typed
return 0;
}

[William Hemsworth]

Congratulations, 3 posts in a row without using code-tags.

[al3x748769]

what do u mean code tags????

[William Hemsworth]

Doesn't anybody read the rules anymore? :icon_neutral:

[death_oclock]

What on earth do you need a binary counter for in a tic tac toe game? Computers store everything in 8-bit binary. How you refer to the number doesn't make a difference, other than maybe speed.

[MosaicFuneral]

What on earth do you need a binary counter for in a tic tac toe game? Computers store everything in 8-bit binary. How you refer to the number doesn't make a difference, other than maybe speed.

They store it in binary yes, but we left the 8-bit addressing range many decades ago - even toys, and appliances have more than that! In the general computer market 32-bit is pretty standard, with a switch towards 64 becoming standard, soon.

[death_oclock]

Sorry, I was talking about the lowest subdivision of data programmers can work with: the byte. Yes, addresses certainly require more than 8 bits.

[viwenka]

They store it in binary yes, but we left the 8-bit addressing range many decades ago - even toys, and appliances have more than that! In the general computer market 32-bit is pretty standard, with a switch towards 64 becoming standard, soon.

It seems like u're good in C=)

So i'm looking for the same program, but without using library just stdio.h

can u help me? maybe just recreate some code?
that code below from the girl, i can't get it, where are input and output?

i need to get binary number from a user.