all i can think i will type here and please explain the others.thank you
this is just to enhance my knowledge about oop.The info i got now isn't enough...
q1
Write a simple program to ask user to input five digits number. Using the input, output the five digits number in reverse order.
solution
#include<stdio.h>
# include<iostream.h>
void main()
{
int a,n,s=0,t;
cout<<"Enter the number=";
cin>>a;
for(n=a;n!=0;n=n/10)>>this is the loop i think to get it in reverse orders correct??
{
t=n%10;<<to get the last digit
s=(s*10+t);<<<<to get output question and make it in order but i am unsure
}
cout<<"The Reverse No. is "<< s<<endl;
}i think using modulus 10 gets the last digit in the digit we inputed and doing modulus 10 again get the second last digit.
am i correct?
q2
Write a program that ask user to input an integer. Pass the input to functions toBase2(), toBase4(), toBase8(), for which each function will output the equivalent of the integer in Base 2, Base 4, and Base 8 respectively.
the equation i guess
89
in base 8 is:
1 * 8 ^ 0 + 3 * 8 ^ 1 + 1 * 8 ^ 2
in base 4:
1 * 4 ^ 0 + 2 * 4 ^ 1 + 1 * 4 ^ 2 + 1 * 4 ^ 3
in base 2:
1 * 2 ^ 0 + 0 * 2 ^ 1 + 0 * 2 ^ 2 + 1 * 2 ^ 3 + 1 * 2 ^ 4 + 0 * 2 ^ 5 + 1 * 2 ^ 6
#include<iostream>
#include<iomanip>
using namespace std;
void tobase2(int a)
{
int z;
cout<<a<<" in base 2: ";
while(a>0)
{
z=a%2;>this is to get the remainder digit left of divide by 2 of 1 or 0
a/=2;>>i wonder what's this use?to make it more efficient?
cout<<z;
}
cout<<endl;
return;
}
void tobase4(int a)
{
int z;
cout<<a<<" in base 4: ";
while(a>0)
{
z=a%4;>>to get the remainder of divide by 4 i guess?
a/=4;>>please explain
cout<<z;
}
cout<<endl;
return;
}
void tobase8(int a)
{
int z;
cout<<a<<" in base 8: ";
while(a>0)
{
z=a%8;>>to get the remainder of divide by 8 i guess?
a/=8;>please explain
cout<<z;
}
cout<<endl;
return;
}
int main()
{
int a;
cout<<"Enter an integer: ";
cin>>a;>>normal input by user
tobase2(a);
tobase4(a);
tobase8(a);
return 0;
}q3
Modify Question 2 so that only one function is created called toBase() which will receive two arguments which is the integer to convert and the base to which the integer will be converted. This function can be used to convert any number to any base. Ask the user to input an integer. Then using the function, iteratively call the function toBase() which will output the integer from Base 2 until Base 10.
so this program receives only base and integer user and outputs of the desired integer in the base is it?
and then it displays the values of the received integer from 2 to 10.
this is wat i understand.
i only got the integer from 2 to 10.
any idea on doing for the desired
#include<iostream>
#include<iomanip>
using namespace std;
void toBase( int a, int b)
{
int z;
cout<<a<<" in base "<<b<<": ";
while(a>0)
{
z=a%b; >>>>to get the remainder and make it divide again.
a/=b;>>not sure need help here
cout<<z;
}
cout<<endl;
return;
}
int main()
{
int a, b;
cout<<"Enter an integer: ";
cin>>a;
for(b=2;b<11;b++)>>the loop from base 2 to 10
{
toBase(a, b);
}
return 0;
}this only input from 2- 10 base of the required integer.
but i need more understanding of this coding.your help is so appreciated
and this is my first assignment for OOP in c++
