output

[Iamateur]

What will be printed as the result of the operation below:

#define swap(a,b)  a=a+b;b=a-b;a=a-b;
void main()
{
int x=5,y=10;
swap(x,y);
printf("%d%d",x,y);
}

[L7Sqr]

It's fairly simple to just compile that and find out yourself. If you don't have a compiler you can translate the macro yourself to get the following source:

void main() {
   int x=5,y=10;
   x=x+y;y=x-y;x=x-y;;
   printf("%d%d",x,y);
}

From that point it's just straight addition and subtraction. You should be able to compute that easy enough.

[Moschops]

http://ideone.com/umhqzJ

[Helper guy]

According my point of view if you want to know the output of this code then it is swaping process
so look below
x=5,y=10;
x=x+y;//x=5+10 now x value is 15
y=x-y;//y=15-10 now y value is 5
x=x-y;//x=15-5 now x value is 10
so it's simple swaping process guys
At the end you will be find value as
x=10 and y=5;

Thanks ..That's all