Problem Printing the whole argv[4]

[amano]

Hello, I have a problem to print the whole string in argv[4]. here's my code

#include<stdio.h>
#include<string.h>
#include<stdlib.h>
#define XMAX 65
#define YMAX 32
char screen[XMAX][YMAX];
void printScreen(void);
void fill(int, int, char[]);
int main(int argc, char *argv[])
{ FILE *in;
int x, y,z;
char a;
if (argc!= 5)
{ fprintf(stderr,"Usage:\n\t%s <65x32 text file> <x> <y> <letter>\n",argv[0]);
exit(1);
}
in = fopen(argv[1],"r");
if (in == NULL)
{ perror("opening input file");
exit(1);
}
for (y=0; y<YMAX; y++)
{ for (x=0; x<XMAX; x++)
screen[x][y] = fgetc(in);
}
if (fclose(in))
{ perror("closing input file");
exit(1);
}
printScreen();
x = atoi(argv[2]);
y = atoi(argv[3]);
a = argv[4][0];

fill(x,y,a);
printScreen();
}
void printScreen(void)
{ int x,y;

for (y=0; y<YMAX; y++)
for (x=0; x<XMAX; x++)
if(screen[x][y]!= EOF)
putchar(screen[x][y]);
else
puts("\n");

}
void fill(int x, int y, char a)
{
if ((screen[x][y] != ' '))
return;

screen[x][y] = a;
fill(x,y+1,a);
fill(x,y-1,a);
fill(x+1,y,a);
fill(x-1,y,a);
}

In my code, i only able to print a character. How shoulld i change my code so that i can print the whole string in argv[4]. If i use argv[4][0], then it will only print the first element of the string in argv[4]

[Ancient Dragon]

variable a should be declared as char*

char* a;

[amano]

variable a should be declared as char*

char* a;

If u don't mind could you please explain more. I'm not good in pointer. Which char a should i change? Is it in function prototype or i should change all of them? OK. Thanks

[Ancient Dragon]

argv is a two-diminsional array of strings. char c is only one character, not a pointer to a character array. you need to declare it as char* a in the 3d line following the declaration of main().

[amano]

argv is a two-diminsional array of strings. char c is only one character, not a pointer to a character array. you need to declare it as char* a in the 3d line following the declaration of main().

int main(int argc, char *argv[])
{ FILE *in;
int x, y;
char *a;
if (argc!= 5)
{ fprintf(stderr,"Usage:\n\t%s <65x32 text file> <x> <y> <letter>\n",argv[0]);
exit(1);
}
in = fopen(argv[1],"r");
if (in == NULL)
{ perror("opening input file");
exit(1);
}
/* Read the 65x32 text file */
for (y=0; y<YMAX; y++)
{ for (x=0; x<XMAX; x++)
screen[x][y] = fgetc(in);
/* To bypass the extra newline character */
}
if (fclose(in))
{ perror("closing input file");
exit(1);
}
printScreen();
x = atoi(argv[2]);
y = atoi(argv[3]);
a = argv[4];
 
fill(x,y,*a);
printScreen();
}

I've changed my code like the above but it still print first character of argv[4]. May I know why?

[Ancient Dragon]

remove the star from the fill function (3d line from the bottom). you should really use [ code=c ] tags so your posted program will have line numbers and you don't have to manually add those color tags.

also, post the function printscreen(), I have no idea what it is.

[WaltP]

Also, to add to what AD mentions, format your code so we can read it.

[amano]

remove the star from the fill function (3d line from the bottom). you should really use [ code=c ] tags so your posted program will have line numbers and you don't have to manually add those color tags.

also, post the function printscreen(), I have no idea what it is.

If i removed the star, the program will give me an error.

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

#define XMAX 65
#define YMAX 32

char screen[XMAX][YMAX];

void printScreen(void);

void fill(int, int, char);

 
int main(int argc, char *argv[])
{
    FILE *in;
    int x, y;
    char *a;
 
   if (argc!= 5)
   {
    fprintf(stderr,"Usage:\n\t%s <65x32 text file> <x> <y> <letter>\n",argv[0]);
    exit(1);
   }
 
   in = fopen(argv[1],"r");
   if (in == NULL)
  { 
      perror("opening input file");
      exit(1);
  }

 
   for (y=0; y<YMAX; y++){
      for (x=0; x<XMAX; x++)
        screen[x][y] = fgetc(in);
  }

 
   if (fclose(in))
  { 
       perror("closing input file"); 
       exit(1);
  }
 
   printScreen();
   x = atoi(argv[2]);
   y = atoi(argv[3]);
   a = argv[4];
 

   fill(x,y,*a);

   printScreen();
}

 
void printScreen(void)
{
     int x,y;
 
    for (y=0; y<YMAX; y++)
     for (x=0; x<XMAX; x++)
       if(screen[x][y]!= EOF)
          putchar(screen[x][y]);
      else
          puts("\n");
 
}

 
void fill(int x, int y, char a)
{
   if ((screen[x][y] != ' '))
     return;
 

   screen[x][y] = a;
   fill(x,y+1,a);
   fill(x,y-1,a);
   fill(x+1,y,a);
   fill(x-1,y,a);
}

[Ancient Dragon]

you have changed that fill function -- your original code took a character array as the second argument, now the latest code only takes a single character. With this code you need to put that star back in.

[WaltP]

Hooo boy....

int main(int argc, char *argv[])
{
...
   fill(x,y,*a);    // remove the *, you will pass in the array

   printScreen();
}

...

void fill(int x, int y, char a)  // Add the *, so the function knows it's a pointer
{
   if ((screen[x][y] != ' '))
     return;
 

   screen[x][y] = a;  // now that it's a pointer, you figure out how to 
   fill(x,y+1,a);     //    do what you want here, especially since you
   fill(x,y-1,a);     //    have no comments explaining what this is
   fill(x+1,y,a);     //    supposed to accomplish.
   fill(x-1,y,a);
}

[amano]

Actually the output of the program will be like this

[IMG]http://img172.imageshack.us/img172/9789/outputbangangmh2.th.jpg[/IMG]

If we choose I as argv[4] then I will fill up the inner part of the output. What i want to make here is instead of character, I want string to fill up the output like 'WOW'. That's the problem I encountered.