Member Avatar for rjusman90 
<?php $picurl=$row['PicUrl']; >?
<td><input type="file" name="userfile" ></td>
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  • Latest Post Latest Post by andrevanzuydam
Member Avatar for andrevanzuydam

I'm not sure the file input can accomodate that, you should use a label around the input and put the file name in there.

echo "<td><label>{$row["PicURL"]} <input type=\"file\" name=\"usefile\"> </label></td>";

Alternatively display the file as an img tag to show the user what has already been chosen?

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