39,316 Topics
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| | I have 3 text fields named "month, day, and year" And 1 hidden field named "Date2" My goal is to have the 3 fields combine to enter as date in Mysql. I've tried this many different ways, the latest having the value of Date2 as [ICODE]<?php echo $year,'-', $month,'-', $day; … |
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| | I have a very simple PHP script which doesn't work correctly for no reason at all, except that I am cursed:scared:!! This is my code and then I will give you the retarded error message I am getting!! [CODE]<html> <form action="get.php" method="GET"> <input type="text" name="myname"><br> <input type="submit" value="click here"> </form> … |
| | Hey, anybody know if there is a DLL available for Image Magick that I can put in the /ext directory and use Image Magick without having to install the Image Magick software? Thanks. |
| | cookies set by cfm may retrieved by php? if iframe have or not (other page)? In a cfm page may insert: <iframe src="country.php" frameborder="0" marginheight="0" marginwidth="0" scrolling="no" width="120" height="14" style=" border:none"></iframe> where country.php: // to get ip I used $_COOKIE['countNumVisitor'] set by cfm, get by php, well seems default NULL … |
| | how detect that a visit to my site is done by a search engine and not by human? the referenceUrl (visitor come from) is always null if search engine auto visit or...? I know to get server params like ip, reURL, etc  |
| | Hi! This is my first post in this forum. Thanks in advance to anyone who can help with this! I hope this makes sense. I'm also relatively new to PHP, so I hope I have used terminology correctly in describing the problem. I am not sure how to accomplish what … |
| | Ii have been working on a shopping cart, the way my cart works is that for each item in a users cart the data is stored in a database. So if the users has a hat and a glove there are 2 rows in my table, the rows are joined …  |
 | How do you create a mission-critical website providing exceptional performance yet at the same time being flexible, reliable and scalable? That's the question that Kyle Loudon, a software developer and manager of a user interface development group at Yahoo!, sets out to provide the answers to in his book: Developing … |
| | Hi guys, could you please check this code for me. basically displaying data from two table. i get error massage like... Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in C:\wamp\www\dis_take.php on line 91 [CODE]<?php $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } … |
| | Hi. I have created a form with 4 textboxes and one listbox. What I want to do is for every record which i select from the list to populate the boxes with information from a MySql database. I have managed to do this for one textbox, but i have a … |
| | Hi everyone I need a bit of help with a problem involving HTML, JavaScript and PHP which I'm hoping someone here can help me with. I have a working PHP script which uses a FORM section to get data input, which actions itself to do some PHP and JavaScript calculations … |
| | Hello folks I am trying to get a PHP variable to pass values to a sample javascript but nothing shows up if I tried to echo the result. I tried passing regular strings as arguments and those worked fine. It just doesn't seem to be working if I tried to …  |
| | hello guys i hav db as to store firstname,lastname,email,addr,city. if i select any id i want that particular row and also at that same page i click next button next row want to preview. please help for this by send code as possible soon |
| | Hi, Its been couple of month i started learning php. I am using xampp, php version 5.3.1, notepad++ to edit. I wanted to use a debugger, so downloaded xdebug5.3vc6 32bit version and DBGp plugin, did the changes as mentioned [URL="http://amiworks.co.in/talk/debugging-php-using-xdebug-and-notepad-part-i/"]here[/URL]. Problem is php is not recognising xdebug. when i run … |
| | i know i should know this but for the life of me i forgot it. what i want to do is within my loop. I want a single variable that has multiple info in it that can be separated by a , ex: loop one { $store = "fieldone='$fieldone'"; } … |
| | [CODE] $_SESSION["srch"] = trim($_GET["search"]); $var = $_SESSION["srch"]; $searchinfo = array(); //////Home $viewQuery1=mysql_query("select * from home_content where hc like \"%$var%\" ") or die(mysql_error()); if(mysql_num_rows($viewQuery1) > 0) { while($Res1 = mysql_fetch_array($viewQuery1)) { $searchinfo[0] .= '<a href="home.php?pk='.$Res1['parent_key'].'">'. substr($Res1['hc'],0, 25).'</a>'; }//while $num = mysql_num_rows($viewQuery1); }//if //////END Home //////HIGHLIGHTS $viewQuery2=mysql_query("select * from highlights where hl_c … |
| | I have a search where I want to be able to search a string of words. The search is going to be looking in 2 different table joined by a left outer join. The tables are "quotes" and "categories". <?php $sql="SELECT q.id, q.username, q.quote, q.by, q.voteup, q.votedown, q.servtime, c.label FROM … |
 | hello... in my site i want to do search images from google and put a link to each image "upload this image". when i click this link automatically upload this image in to my site. i searched a lot after i found this script. but how to add link and … |
| | I have a problem that I cannot for the life of me find a solution to and since I have received assistance on this forum before I thought I would give it a try here again. I posted this question earlier but I did not have time to finish it … |
| | I am trying to display the number of rows I have in my database, but instead of the number being displayed on my page I just get the word 'array' My code is below [CODE] $productCountSql = "SELECT COUNT(*) FROM products WHERE `user_id` = '" . $_SESSION['user_id'] . "'"; $productCountResult … |
| | I bought the book "PHP 5/mySQL Programming for the Absolute Beginner." So far I have been pleased with the book, but am stuck on a lesson and can't get past it, because the code given is either not correct(I did find an error in another lesson) or my webserver won't … |
| | I have an update statement which should update a product using information the user has submitted from a form The error being that nothing gets updated, the sql code does nothing, and changes nothing in the database Can anyone see an error in the code? [CODE] $user_id = ($_SESSION['user_id']); $product_id … |
| | Hi, Say for example I have a page with 100 includes. How would I reload just one of them? Say I ran an ajax script that did certain tasks on the server side, but I didn't want to display the information by setting it in the ajax script - Instead … |
| | I'm sure this is stupidly simple, but I havent been able to figure it out with lots of Google searching and pouring through tutorials. I'm building a simple computer trade-in value calculator PHP app. Using a form to select the type of computer and the various specs, I need it … |
| | I am trying to write a script that you input a phone number, and it outputs the address and name the number is listed under. How do i do this? Please help me. I will be very grateful.  |
| | good afternoon all, i am currently writing a system in PHP that requires interface with a USB thermal receipt printer for a friend upon form submission. currently i have read about interfacing with devices containing a parallel port but there has not been much detail on how i can use …  |
| | Hello: I have the following challenge I need assistance with. I have a mysql table [CODE] -- phpMyAdmin SQL Dump -- version 3.3.3 -- http://www.phpmyadmin.net -- -- Host: localhost -- Generation Time: Dec 01, 2010 at 01:22 PM -- Server version: 5.1.48 -- PHP Version: 5.2.13 SET SQL_MODE="NO_AUTO_VALUE_ON_ZERO"; /*!40101 SET … |
| | Hi All, Im trying to count the number of instances of a value in an array and put that value into a variable but im a little stuck. My example below prints to screen how many of each, but i want it broken down to a specific variable of that … |
 | [CODE]<?php $con = mysql_connect("localhost","root","" ); mysql_select_db("test",$con); $sql="select image from image"; $res=mysql_query($sql) or die(mysql_error()); $i=1; while($i < mysql_num_rows($res)) { $image_id[$i] = mysql_result($res, $i); echo "<img src=\"".$image_id[$i]."\">"; $i++; } ?> [/CODE] I'm using this code to display the image from mysql but images are shown like this M¢—‡¤6n幆J1³ŒªÌF· æFLùp1 `‘ã:ÃDVNÒ–¢Q SgWñg€?´‘íx3²ûEùÝ ô.l%·ËìÈŒÿAzH'óÀËË€XƒÍ«L²GçÚ›9ást¸ °äŒëŸ]˜¦21ŒÖ| ¸E^®ÏJOXX&æàߣéü6bêæ¬Öò7aúQ¡·÷9;Ó-ˆ )ôd x¹cüÖlÒ'j( q1ÌnéW4Ó÷dÇå©uF … |
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