Hi and sorry if this is the wrong forum but didn't know where to place my question. I need to know the answer of a+b=23. So how would I calculate the values of a and b and the same would apply for a^b=16. So basically I need to know the algebraic equation to find the original numbers. Does anybody know where I can find such a formula as I am trying to reverse a formula. Thanks...
cwarn23 387 Occupation: Genius Team Colleague Featured Poster
Rashakil Fol 978 Super Senior Demiposter Team Colleague
If a + b = 23 and a^b = 16, well, you know that a = 23 - b, which means (23 - b) ^ b = 16.
So here's what you should do. Write (23 - b) ^ b - 16 = 0, and then use Newton's method to find the zero of that equation. You know how to differentiate (23 - b) ^ b, right? Haha, that's one of the harder ones. Good luck.
cwarn23 387 Occupation: Genius Team Colleague Featured Poster
The equations a+b and a^b were two separate questions. So do you know how I would solve that?
Rashakil Fol 978 Super Senior Demiposter Team Colleague
If they're separate questions then each question has infinitely many solutions. And it should be pretty obvious, if you know the basics of [s]algebra[/s] obviosity.
iamthwee commented: Just the right amount of help and not too much. +11
mrnutty 761 Senior Poster
>> a+b=23
Not taking into account floating points and just positive natural numbers. Then
if b > 23 then no Answer Possible
if b = 23, then a = 0;
if b = 22, then a = 1
if b = 22, then a = 2
General Equation : B = 23 - a OR A = 23 - b
Following this pattern b could be from 23 - 0 and a could be from 0 - 23
So there are 2 * 23 = 46 different solutions.
If thats not it then clear up what you want.
Rashakil Fol commented: A useless comment designed to congratulate oneself for knowing basic obviosity... only you messed up and made a mistake -1
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